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Video instructions and help with filling out and completing Shared well two pressure tanks

Instructions and Help about Shared well two pressure tanks

So I had multiple weld tanks left up to this system it's good to have backup tanks for a lot of reasons in case you have first of all by having more than one tank you can increase your pressure on the pressure switch and without really costing you too much capacity because as you increase the pressure on your pressure switch you have to increase the air pressure in this tank and ultimately it reduces the capacity of the tank so if you have a second tank or a third tank you can get more so in this case I have three 20 gallon tanks each one has a capacity of about five gallons and I have it set at 40 39 psi s when it kicks on 54 psi kicks off right now so I reduce the height the high end screw on the pressure switch to try to get a lower maximum but I increase the main screw and the pressure switch to get a higher minimum so dick pump doesn't have to kick on very often because it has 15 gallons to work with here but you always have a pressure in the 40s which is beneficial for my reverse osmosis system for one thing so I got these tanks on Craigslist and sometimes you have to clean them up paint them if they're not too old they can be in decent shape you gotta make sure that it can hold air pressure first and if that's good to go then you got to make sure it'll hold water pressure and of course you want to make sure it's not waterlogged so when the tank is then empty if it still feels heavy there's water sloshing around it means there's a problem with the liner and generally speaking in most cases it's a throwaway in that situation you can get a brand new tank on Amazon for about $137 so if you buy if you're buying one used and it's got a busted bladder it's probably not worth messing with it but if you do have one that's you know only a couple years old and you got a good really good deal on it I say why not have a couple of them in this case it's a flow tech and it has a plastic flange with a female one-inch so I used a couple of one inch male adapters glue them together with a piece of one-inch PVC and I really like to screw plastic into plastic in this particular case I really wouldn't want to put a stainless steel nipple into that female plastic fitting so what I did was actually wrap these with four layers of thick Teflon tape and then I painted it with a layer of thread compound it gives you a perfect seal every time I mean it's a little extra work it's a little messy Bloodsworth it you don't want to have any trips and then I.


“Which Tank will Will Fill up First? (example with 12 tanks, A to L, see question source for image)
This is a recent meme that’s getting shared on facebook and elsewhere. Repeating the image from the question source:This is a question that has gone viral recently. Most people answer “G”.But look closely, as the question says. Many of the pipes are blocked - the line that blocks off D from C is not a mistake.To find the real answer (this is assuming a low flow rate, as after all it is shown as a drip in the diagram):From A to B to C is straightforward. None of them can fill before the next one.J is a bit more complex. But as you fill J, as soon as the water rises to the outlet to L it overflows to L. So it can never get any higher. Yes, its level also rises in the outlet tube leading to I, but it can never get high enough to overflow to I.So it flows to L, which in turn fills F.So which fills first, L or F?By the time F is full, L will only be partly full (with the water at the same level for both).So your F is the answer.This video shows the idea, an animation by Nick Rossi using a physics engine, AlgodooIt doesn't quite flow like a real fluid, as he says, but it's enough to get the answer and show how it works.Here is another animation Which will fill first? from THE FLOW... by CorneliaXaosWhich will fill first? by CorneliaXaosThat answers the question, since it shows a dripping tap at a slow flow rate. But let’s go off on a tangent.WHAT HAPPENS IF THE WATER IS POURED INTO A AT A FASTER FLOW RATEIf the flow is very fast then obviously A will fill first. However, could any of the others fill up first before F and before A?It’s• governed by the Hagen–Poiseuille equation so long asthe flow is due to a pressure difference.the fluid is incompressible and Newtonian (water is, approximately).the flow is laminar (not turbulent) - it is with water if it flows slowly through a narrow pipe.through a pipe of constant circular cross-sectionthat is substantially longer than its diameter,and there is no acceleration of fluid in the pipe.All those conditions seem to apply. The pipes are substantially longer than their diameter which is one of the most important requirements. And they are narrow, and the fluid is water.Under those conditionsIf the outlet is above water, the flow rate is proportional to the height of the head of water above the inlet to the pipe. If the outlet is below water, it’s proportional to the difference in height between the water above the inlet and the water above the outlet.The difference in height of the water here is often called the “head” of water.It is inversely proportional to the length of the pipe.Or in short, the flow rate for laminar flow, in a pipe significantly longer than its diameter, is proportional to the pressure difference, and so to the head of water, but it is also inversely proportional to the length of the pipe.(it also depends on the radius of the pipe and the viscosity of the water but those are the same for all our pipes).Techy details. The equation is:There L is the length of the pipe and R is its radius.Q is the flow rate (what we are looking for).ΔP is the difference in pressure between the two ends of the pipe, which for water is proportional to the difference in height of the inlet and the outlet.Finally μ is the dynamic viscosityAll of those are constant (the pipes are all the same radius, and the viscosity is constant) except for L, the length of the pipe, Q which we are interested in and ΔP.So our equation simplifies to Q = c ΔP / L, where c is a constant which is the same for all the pipes in our example because they are all the same radius.Double the length of the pipe and you halve the flow rate. Double the head and you double the flow rate.So now for instance, can L fill at any flow rate?Its outlet is a very long pipe. Even if L is nearly full of water ,the head of water in F will mean the difference in heads between L and F is quite small even if F is nearly full and L is likewise.Its inlet is a much shorter pipe. Whether L can fill will depend on whether we can get J to have a high head to increase the flow rate of L's inlet pipe to more than that of its outlet pipe. But, at least at first sight, it would seem that such a high flow rate could mean that one of the other tanks earlier in the chain could fill firstSo - it’s quite a finely balanced question, and hard to answer.A obviously can fill first with a very fast flow rate, just fill it faster than it can empty.Well we can actually try this out with a real world experiment :).Well we can actually try this out with a real world experiment :).Prozix has made a 3D printed version of the puzzle. If you have a 3D printer you can download it here and print it out and test it yourself: Answer to the question Which one fill First / water equisystem by prozixI don’t have a 3D printer but he has uploaded some videos.First this is what happens with a slow flow rateNote that at 22 seconds in, J nearly fills briefly.If you look closely, you see that a bubble forms in the outlet from J to L, which makes sense, it’s a downward pipe and air is buoyant. The bubble then gets pushed out into L and then bursts.This shows the bubble just before it bursts (you can show the video at 1080p from the Settings)So - if the pipes are very thin - or the flow is just right - that might lead to J filling right there, if you can arrange it to fill before the bubble disperses.So even at a slow rate we have something anomalous already, though its because of a bubble.But what happens at faster flow rates? I asked in a comment to the video, and Prozix was interested and answered with a new videoAt 28 seconds in, at one of the flow rates, then L and F fill at the same time.Here, it all makes sense up to J. J can’t fill (apart from that possibility due to the bubble) at this stage because the pipe from C to J has only a tiny head above its inlet. It’s outlet is about twice as long as its inlet, perhaps more.Aside: If C was nearly full, J would start to fill, and if we could have the level of water stay below the outlet into L while J fills, then C with its shorter pipe could continue to fill J even when it is nearly full. But as it is now, there is no chance of J filling.So that makes sense. But how can F fill at the same time as L? That's more mysterious.The pipe from L to F is three times the length of the pipe from J to L. Meanwhile, in the situation shown here, the head from J to L is about double the head from L to F.So by the Hagen Pousseville equation again, the flow rate from L to F should be about two thirds of the flow rate from J to L in this situation where J is half full and both L and F are almost full.So you expect L to fill faster than F.So, I don’t think they can get into this situation at all, with a steady flow into L. There must be something going on that doesn’t fit our assumptions of laminar flow, or something else such as a bubble forming.Let’s look at what lead up to this. If you look at the video, L fills faster than F to start with, keeping nearly the same head from L to F as from J to L.L is clearly filling faster than F and is on track to beat it. There is no sign of any bubbles in the inlet to L.But then a little while later you get this (25 seconds in)Now F is filling faster than J. Something has happened to reduce the flow rate into L, which then permits the two levels between L and F to equalize.But the head going into L hasn’t changed. Also the input pipe to L is full and there are no bubbles. I think the only possible answer is turbulence.You can see waves forming in J so maybe that means there’s a bit of turbulence impeding the flow from J to L, especially since the water level for J is exactly at the level for the outlet to L. What are your thoughts?This is what happened with a moderately fast flow rate:Here is the video starting at that point.All of A, B, C, J, L and F are just about full. B, L and F started to overflow first and I think L just about beat the other two though it was almost simultaneous. In this frame you can see L just about to overflow and the other two though they have the water raised above the level of the top, haven’t yet actually started to flow down the side.So how do we understand that as a possible state in terms of the flow rates? Back to our diagram againWith A, B, C, J, L and F all filled, then A to B to C to J all have the same length of pipe and same head (height difference of the water in the tanks above inlet and outlet) so have the same flow rate. J to L has around 2.5 times the head of C to J, and the pipe is around 2.5 times the length, so the flow out of J is about the same as the flow into it, and the difference in head between the top of J and the outlet to I is small. From L to F, the difference in head is about the same as for C to J (which we already know is about the same as the flow from J to L) but the pipe is far longer, so L shouldn’t be able to empty as fast as it fills, and the water flows out of J faster than it flows out of L, so L should fill before J.From L to F, the difference in head is about the same as for C to J but the pipe is far longer, so L shouldn’t be able to empty as fast as it fills, so it should fill long before J fills,So if the flow rate is high enough for J to fill like this, L should fill before J and F doesn’t get a look in.So how could it happen? Well it could be the bubble from J to L, slows down the flow out of J so that J fills first before L.As for F filling, how did that happen? Let’s look at it again:The head from J to L is far higher than from L to F and the pipe is shorter, so the flow into L should be a lot more than the flow out of L to F. So it seems impossible for F to fill like this. It's not the bubble - the two tanks fill up reasonably steadily at the same rate. You can watch the video at quarter speed to check. Click the Settings icon in the lower-right corner, then click the Speed selector.Perhaps at this flow rate, its the double kink in the pipe from J to L causing more turbulence and so slowing down the input to L? What do you think? That could also help explain why J fills at this flow rate, if the pipe from J to L, has a slower flow rate than you’d expect from its length and head. What do you think? Do say in the comments.Even K can fill, though it is pretty hard to do. This is with a very strong flow into A, and several of the others have been overflowing for some time. They have turned off the inlet pipe at this point.Amusingly, in the real world, E ends up half full too after some time of running it at a high flow rate with the water overflowing from A.Here is the complete videoSo far the only confirmed alternatives to F are A (obviously) and L (pretty sure it wins at the moderate flow rate).That’s just a start. There are many other things to tryVarying flow rate. Can you get, J, say, to fill first or even K by turning the flow rate up and down at critical points during the filling process? This could cause bubbles to form, as well as adjust the heads of the various tanks.What happens if you scale the whole model up, or scale it down to a very small size? Scaling it down could make the flow rates out of some of the pipes very slow. It could also mean that bubbles like the one from J to L take a long time to disperse too. Scaling up could lead to more possibility of turbulent flow through the pipes.Try adding sugar for viscosityWhat if it is really hot, and you use a slow flow rate so that the water evaporates quickly?What if it is really cold so that the water freezes? That would seem to be a way to fill even B first, if the water freezes by the time it gets to B to C but remains unfrozen as far as the flow from A to B.NOTEIf you see anything in this to correct, however small or important it is, please either suggest an edit for my answer or say in a comment. Thanks!
How is the carbon dioxide to fill pressurized tanks produced?
Carbon dioxide is produced by a lot of industrial operations, including combustion, steam methane reforming, limestone baking, fermentation, scrubbing of oil and gas streams, and a minor product from industrial air separation.  In practice, the purest streams tend to come from steam methane reforming and from fermentation and these are the only ones that tend to be captured.  SMR produces most types of industrial grade gas, while fermentation gas as well as some purified carbon dioxide from SMR is generally used for food-grade carbon dioxide.The easiest way to obtain a source of carbon dioxide for pressurization is likely to be collecting the gas from an anaerobic fermentation, which you might be able to find easily if you know anyone who home-brews beer.  Once the fermentation has gotten started, the gas coming out of the lock will functionally contain carbon dioxide, some residual nitrogen, and water.  Unfortunately, pressurizing this in a home environment is hardly easy.  The biggest problem you will have is that the gas coming out of the lock will be wet - that is, saturated with water - and wet carbon dioxide under pressure is very corrosive due to the formation of carbonic acid.  Carbon dioxide cylinders are pressurized with dry gas to avoid this.  For example, specs for various grades of carbon dioxide from Praxair are here: Page on PraxairNote that in each case, the water content is extremely low - 3 ppm in all cases.  Also note that despite your wild expectations, THC doesn't refer to tetrahydrocannabinol but is an acronym for "total hydrocarbons."  Sorry ,)In order to dry your own gas, you will probably have to go through several steps to get the water out.  In an industrial setting, people generally use a hygroscopic reagent such as triethylene glycol (TEG) to scrub the water from gas streams.   Unfortunately, you're not likely to have access to that.I would recommend a series of methods to get out as much water as you can.  First, refrigerate the stream in some kind of decanting tank to condense out as much of the contained water as you can.  Industrially, gas streams can be functionally dehydrated by freezing down to about -150 degrees Fahrenheit, but you're not likely to do better than about 20 degrees F - however, every little bit helps.   The next step would be to pass the gas stream through a column packed with a dessicant, most commonly anhydrous calcium chloride (CaCl2).  Anhydrous calcium chloride is well suited for the application because it readily forms several hydrates and then finally a very concentrated brine, which should be collected in a drip pan below the gas inlet.  Calcium chloride dehydrators have been known to get as low as 1 lb water/MMscf of gas, enough to meet industrial gas specifications.  You can get calcium chloride easily - it's the most commonly sold road salt and is available basically everywhere in snowy areas.There are some calculations involved in all of this, ideally you will have some knowledge of the water content of your gas by looking at the amount of water in some representative amount of carbon dioxide released from the fermentation vessel at the outlet temperature.  From the water content of saturated gas at your refrigeration temperature, you will have some idea of the amount of water you can expect to collect there.  For the remainder, you have to design your dessicator to ensure that the gas both moves slowly enough to allow the dessicator to work and contains enough calcium chloride to properly dessicate the gas.  In general, you want a length:diameter ratio on the bed of about 3:1 or more, and at least 0.3 lb of calcium chloride for each lb of water you expect to remove.  The most important design parameter in this case is the superficial bed velocity, which determines the length of your dryer.  Based on the cross-sectional area of your inlet pipe, the gas velocity at the inlet pipe, and the cross-sectional area of the column, you want to try for about 20-30 ft/min.
If two tanks of area in ratio 1:2 are filled with water to the same height, what will be the pressure at the base of both tank?
The pressure at the bottom of both tanks would be the same.First reaction of most people would be to assume that the tank with larger area is holding more water, meaning more weight and more force, hence more pressure. But this not the case. They have just encountered the ‘Hydrostatic Paradox’.The pressure at a depth inside a fluid, is given by -P = [math]\rho[/math] * g * hGiven same fluid is filled in both, the only parameter which would influence the pressure at the bottom is the depth of the liquid column.In your question you have only mentioned tanks, which we can assume is cylindrical. This result holds good even for unevenly sized tanks.The paradox arises from the fact that people assume that if there is more fluid (meaning more weight), it will result in greater forces, hence greater pressures.Consider this setup, in flask B, there is more fluid, but same base area. So the assumption ( which is wrong) is that pressure at point B would be more.The paradox can be explained by considering how the forces act. he pressure at a point in a static liquid is due entirely to the weight of liquid (plus the atmosphere) directly above it. The liquid exerts a pressure at right angles to the wall. What is important to consider, is that the wall also exerts a force on the liquid, the vertical component of which nullifies the weight.Irrespective of the size/shape of the vessel, the same thing holds true. Only the vertical column over the base contributes to pressure, which is solely dependant on the height of the column.
How do water well pressure tanks work?
There’s a flexible gastight membrane inside with a gas charge on one side, the water goes into the other side, the membrane splits the tank into two compartments. As the tank pressurises the gas compresses and the membrane stretches to allow the tank to fill with water until the compression limit is reached. When the pump switches off the compressed gas (usually air) keeps the pressure in the tank high. As water is discharged the pressure reduces until a pressure sensor starts the pump again and restarts the cycle.This arrangement is used to prevent the pump from short-cycling and to even out the pressure in the fed main.
A water pipe can fill half a tank of water in two hours. How much time will it take to fill five such water tanks?
Assuming that the water flow-rate of the pipe is uniform:time required for filling half a tank= 2 hourstime required to fill the tank completely= 2 x 2 = 4 hourshence, time required to fill five such tanks= 4 x 5 =20 hours
Musicians: How many songs do you think you'd need to perform to fill out a two-hour gig?
A two-hour gig? That's 120 minutes of on stage performance or setup inclusion? I'll go with stage time, and also assume you've negotiated appropriate setup, and such.Another assumption is genre. I'll assume it's pop structured (as most radio friendly music is these days), so average song time would be roughly 3 and a half minutes…give or take.You're looking at roughly 30 songs. Thats…over 2 hours. Now, that's a rough estimate, as song times vary, etc.Oh, but wait. You'll need to include breaks, for “personnel” i.e. the band members. Normally, the drummer will need the longest break, followed by others. The drummer is using all four limbs continuously, so…they need them.If you're headlining, and depending on what you've negotiated, you might not be allotted “dead air”, so someone's staying on stage on breaks. Usually, that means at least a guitar player and/or the singer. Maybe not a long guitar solo, but…maybe an acoustic filler/singalong for the crowd. Plus, in between banter, there's that too (paring that down was always a plus for us back in the day)So, practice 30ish and get them flawless, because you're only going to need 20ish. Why 30ish? Because…more is good for flexibility. Always. Plus, it allows you to keep your set list semi-”fresh”, while only putting in a little extra work.setlist.fm - the setlist wiki is a good resource for structuring a setlist in a professional way (I wish it was around during the “trial and error” days.)
If two pipes function simultaneously, the tank will be filled in 12 hours. One pipe fills a tank 10 hours faster than other. How many hours does it take for the 2nd pipe to fill the tank?
Pipe A takes, say x hours to fill the tank. So Pipe A fill (1/x) of the tank in 1 hour.Pipe B takes, say (x+10) hours to fill the tank. And, Pipe B fill 1/(x+10) of the tank in 1 hour.Pipes A and B together fill (1/x)+1/(x+10) or (x+10+x)/x(x+10) = 1/12 of the tank in 1 hour.(x+10+x)/x(x+10) = 1/12, or(2x+10)/x(x+10) = 1/12, or24x+120 = x^2+10x, orx^2–14x-120 = 0(x-20)(x+6) = 0,x = 20. [-6 is inadmissible, here].So Pipe A takes 20 hours and Pipe B takes 30 hours to fill the tank, individually.Check: (1/20)+(1/30) = (3+2)/60 = 5/60 = 1/12 in one hour. Or, Pipes A and B will fill the tank in 12 hours. Correct.
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